What are the solutions to the equation h^2=2^2+2^2 ?

The solutions to the equation h^2=2^2+2^2 are h=2sqrt(2),h=-2sqrt(2)

Find the zeros of h^2=2^2+2^2

The zeros of h^2=2^2+2^2 are h=2sqrt(2),h=-2sqrt(2)

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h^{2} = 2^{2} + 2^{2}

h = 22, h = - 22

Decimal Notation

h = 2.82842 \dots, h = - 2.82842 \dots

Solution steps

h^{2} = 2^{2} + 2^{2}

Simplify

2^{2} + 2^{2} : 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

h = 8, h = - 8

8 = 22

- 8 = - 22

h = 22, h = - 22

\frac{3 x + 1}{2 x - 1} \geq 6

n^{2} + 7 n - 8 = 0

6 x - 6 = 18

- 2 - 5

\frac{11 t}{30} - \frac{t}{6} = 1

What are the solutions to the equation h^2=2^2+2^2 ?
The solutions to the equation h^2=2^2+2^2 are h=2sqrt(2),h=-2sqrt(2)
Find the zeros of h^2=2^2+2^2
The zeros of h^2=2^2+2^2 are h=2sqrt(2),h=-2sqrt(2)