What are the solutions to the equation 4-2x-x^2=0 ?

The solutions to the equation 4-2x-x^2=0 are x=-1-sqrt(5),x=sqrt(5)-1

Find the zeros of 4-2x-x^2=0

The zeros of 4-2x-x^2=0 are x=-1-sqrt(5),x=sqrt(5)-1

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4 - 2 x - x^{2} = 0

x = - 1 - 5, x = 5 - 1

Decimal Notation

x = - 3.23606 \dots, x = 1.23606 \dots

Solution steps

4 - 2 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 4 = 25

x_{1, 2} = \frac{- ( - 2 ) \pm 2 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 2 5}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 2 5}{2 ( - 1 )} : - 1 - 5

x = \frac{- ( - 2 ) - 2 5}{2 ( - 1 )} : 5 - 1

The solutions to the quadratic equation are:

x = - 1 - 5, x = 5 - 1

481

9 - 7 x = (4 x - 3)^{2} + 5

(2 - 3) (2 + 3)

- 75 = m - 123

4 x^{4} m - 36 y^{4} m

What are the solutions to the equation 4-2x-x^2=0 ?
The solutions to the equation 4-2x-x^2=0 are x=-1-sqrt(5),x=sqrt(5)-1
Find the zeros of 4-2x-x^2=0
The zeros of 4-2x-x^2=0 are x=-1-sqrt(5),x=sqrt(5)-1