What are the solutions to the equation (5y+7)(8+y)=0 ?

The solutions to the equation (5y+7)(8+y)=0 are y=-7/5 ,y=-8

Find the zeros of (5y+7)(8+y)=0

The zeros of (5y+7)(8+y)=0 are y=-7/5 ,y=-8

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(5 y + 7) (8 + y) = 0

y = - \frac{7}{5}, y = - 8

Decimal Notation

y = - 1.4, y = - 8

Solution steps

(5 y + 7) (8 + y) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 y + 7 = 0 or 8 + y = 0

Solve

5 y + 7 = 0 : y = - \frac{7}{5}

Solve

8 + y = 0 : y = - 8

The solutions to the quadratic equation are:

y = - \frac{7}{5}, y = - 8

\frac{9 ( x - 2 )}{4} - \frac{7 ( x - 1 )}{3} = 6 x + 1

6108

14 x^{2} + 31 x + 15

x^{3} + 2 x^{2} - 4 x - 8

- x^{2} + 7 x - 12 < 0

What are the solutions to the equation (5y+7)(8+y)=0 ?
The solutions to the equation (5y+7)(8+y)=0 are y=-7/5 ,y=-8
Find the zeros of (5y+7)(8+y)=0
The zeros of (5y+7)(8+y)=0 are y=-7/5 ,y=-8