What is 1/x+1/(x+1)< 2/(x+3) ?

The solution to 1/x+1/(x+1)< 2/(x+3) is -3<x<-1\lor-3/5 <x<0

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1/x+1/(x+1)< 2/(x+3)

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 3}

- 3 < x < - 1 or - \frac{3}{5} < x < 0

Interval Notation

(- 3, - 1) \cup (- \frac{3}{5}, 0)

Decimal Notation

- 3 < x < - 1 or - 0.6 < x < 0

Solution steps

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 3}

Rewrite in standard form

\frac{5 x + 3}{x ( x + 1 ) ( x + 3 )} < 0

Identify the intervals

- 3 < x < - 1 or - \frac{3}{5} < x < 0

18 b^{2} + 84 b + 48 = 0

2 x^{2} + 21 x + 49

3 y < 15

6 a^{3} - 30 a^{2} b + 10 a b^{2}

\frac{x}{3} + \frac{3 x}{4} = 2

What is 1/x+1/(x+1)< 2/(x+3) ?
The solution to 1/x+1/(x+1)< 2/(x+3) is -3<x<-1\lor-3/5 <x<0