What are the solutions to the equation 2b^2+3b+1=0 ?

The solutions to the equation 2b^2+3b+1=0 are b=-1/2 ,b=-1

Find the zeros of 2b^2+3b+1=0

The zeros of 2b^2+3b+1=0 are b=-1/2 ,b=-1

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2 b^{2} + 3 b + 1 = 0

b = - \frac{1}{2}, b = - 1

Decimal Notation

b = - 0.5, b = - 1

Solution steps

2 b^{2} + 3 b + 1 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

3^{2} - 4 \cdot 2 \cdot 1 = 1

b_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 2}

Separate the solutions

b_{1} = \frac{- 3 + 1}{2 \cdot 2}, b_{2} = \frac{- 3 - 1}{2 \cdot 2}

b = \frac{- 3 + 1}{2 \cdot 2} : - \frac{1}{2}

b = \frac{- 3 - 1}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

b = - \frac{1}{2}, b = - 1

- 7 x - 36 = 20 - 3 x

(16 x^{2} y^{4}) (\frac{1}{4} x^{5 y})

16 x^{7} - 81 x^{3}

6 = 2 (x - 2)

- \frac{1}{2} m = - 9

What are the solutions to the equation 2b^2+3b+1=0 ?
The solutions to the equation 2b^2+3b+1=0 are b=-1/2 ,b=-1
Find the zeros of 2b^2+3b+1=0
The zeros of 2b^2+3b+1=0 are b=-1/2 ,b=-1