What is -7n+2(9n+3)>= 4n+10-1 ?

The solution to -7n+2(9n+3)>= 4n+10-1 is n>= 3/7

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-7n+2(9n+3)>= 4n+10-1

- 7 n + 2 (9 n + 3) \geq 4 n + 10 - 1

n \geq \frac{3}{7}

Interval Notation

[\frac{3}{7}, \infty)

Decimal Notation

n \geq 0.42857 \dots

Solution steps

- 7 n + 2 (9 n + 3) \geq 4 n + 10 - 1

Add/Subtract the numbers:

10 - 1 = 9

- 7 n + 2 (9 n + 3) \geq 4 n + 9

Expand

2 (9 n + 3) : 18 n + 6

- 7 n + 18 n + 6 \geq 4 n + 9

Add similar elements:

- 7 n + 18 n = 11 n

11 n + 6 \geq 4 n + 9

Move

6

to the right side

11 n \geq 4 n + 3

Move

4 n

to the left side

7 n \geq 3

Divide both sides by

7

n \geq \frac{3}{7}

19 + 13 x = 32

(i)^{4}

x^{3} - 2 x - 1

\frac{x + 32}{x + 6} \leq 3

n^{2} + n - 22526 = 0

What is -7n+2(9n+3)>= 4n+10-1 ?
The solution to -7n+2(9n+3)>= 4n+10-1 is n>= 3/7