What are the solutions to the equation 7p^2=-40p-25 ?

The solutions to the equation 7p^2=-40p-25 are p=-5/7 ,p=-5

Find the zeros of 7p^2=-40p-25

The zeros of 7p^2=-40p-25 are p=-5/7 ,p=-5

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7 p^{2} = - 40 p - 25

p = - \frac{5}{7}, p = - 5

Solution steps

7 p^{2} = - 40 p - 25

Move

25

to the left side

7 p^{2} + 25 = - 40 p

Move

40 p

to the left side

7 p^{2} + 25 + 40 p = 0

Write in the standard form

a x^{2} + b x + c = 0

7 p^{2} + 40 p + 25 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 7 \cdot 25}{2 \cdot 7}

4 0^{2} - 4 \cdot 7 \cdot 25 = 30

p_{1, 2} = \frac{- 40 \pm 30}{2 \cdot 7}

Separate the solutions

p_{1} = \frac{- 40 + 30}{2 \cdot 7}, p_{2} = \frac{- 40 - 30}{2 \cdot 7}

p = \frac{- 40 + 30}{2 \cdot 7} : - \frac{5}{7}

p = \frac{- 40 - 30}{2 \cdot 7} : - 5

The solutions to the quadratic equation are:

p = - \frac{5}{7}, p = - 5

5 n^{2} - 80

\frac{2}{5} + \frac{2}{5}

\frac{2 π}{4 π}

\frac{1}{8} - 3

\frac{5}{\frac{2}{3}}

What are the solutions to the equation 7p^2=-40p-25 ?
The solutions to the equation 7p^2=-40p-25 are p=-5/7 ,p=-5
Find the zeros of 7p^2=-40p-25
The zeros of 7p^2=-40p-25 are p=-5/7 ,p=-5