What are the solutions to the equation 4x^2+4=0 ?

The solutions to the equation 4x^2+4=0 are x=i,x=-i

Find the zeros of 4x^2+4=0

The zeros of 4x^2+4=0 are x=i,x=-i

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4 x^{2} + 4 = 0

x = i, x = - i

Solution steps

4 x^{2} + 4 = 0

Move

4

to the right side

4 x^{2} = - 4

Divide both sides by

4

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

\frac{x - 6}{x + 2} \geq 0

(x - y)^{2} + 4 (x - y) + 3

∣ 8 x + 4 ∣ < 28

\frac{a + 1}{a ^{2} - a} - \frac{a + 2}{2 a ^{2} - 2}

- 5 x + 8 \leq 23

What are the solutions to the equation 4x^2+4=0 ?
The solutions to the equation 4x^2+4=0 are x=i,x=-i
Find the zeros of 4x^2+4=0
The zeros of 4x^2+4=0 are x=i,x=-i