What are the solutions to the equation 7z^2-8z-21=0 ?

The solutions to the equation 7z^2-8z-21=0 are z=(4+sqrt(163))/7 ,z=(4-sqrt(163))/7

Find the zeros of 7z^2-8z-21=0

The zeros of 7z^2-8z-21=0 are z=(4+sqrt(163))/7 ,z=(4-sqrt(163))/7

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7 z^{2} - 8 z - 21 = 0

z = \frac{4 + 163}{7}, z = \frac{4 - 163}{7}

Decimal Notation

z = 2.39530 \dots, z = - 1.25244 \dots

Solution steps

7 z^{2} - 8 z - 21 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 7 ( - 21 )}{2 \cdot 7}

(- 8)^{2} - 4 \cdot 7 (- 21) = 2163

z_{1, 2} = \frac{- ( - 8 ) \pm 2 163}{2 \cdot 7}

Separate the solutions

z_{1} = \frac{- ( - 8 ) + 2 163}{2 \cdot 7}, z_{2} = \frac{- ( - 8 ) - 2 163}{2 \cdot 7}

z = \frac{- ( - 8 ) + 2 163}{2 \cdot 7} : \frac{4 + 163}{7}

z = \frac{- ( - 8 ) - 2 163}{2 \cdot 7} : \frac{4 - 163}{7}

The solutions to the quadratic equation are:

z = \frac{4 + 163}{7}, z = \frac{4 - 163}{7}

in t (x 9 - x^{2}) d x

lo g_{9} (\frac{1}{27})

y^{2} - 16 x^{2}

- 12 < 3 z - 9 \leq 18

25 - 4 x^{2}

What are the solutions to the equation 7z^2-8z-21=0 ?
The solutions to the equation 7z^2-8z-21=0 are z=(4+sqrt(163))/7 ,z=(4-sqrt(163))/7
Find the zeros of 7z^2-8z-21=0
The zeros of 7z^2-8z-21=0 are z=(4+sqrt(163))/7 ,z=(4-sqrt(163))/7