What are the solutions to the equation 3x^2-24x+46=0 ?

The solutions to the equation 3x^2-24x+46=0 are x=(12+sqrt(6))/3 ,x=(12-sqrt(6))/3

Find the zeros of 3x^2-24x+46=0

The zeros of 3x^2-24x+46=0 are x=(12+sqrt(6))/3 ,x=(12-sqrt(6))/3

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3 x^{2} - 24 x + 46 = 0

x = \frac{12 + 6}{3}, x = \frac{12 - 6}{3}

Decimal Notation

x = 4.81649 \dots, x = 3.18350 \dots

Solution steps

3 x^{2} - 24 x + 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 46}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 \cdot 46 = 26

x_{1, 2} = \frac{- ( - 24 ) \pm 2 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 2 6}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 2 6}{2 \cdot 3}

x = \frac{- ( - 24 ) + 2 6}{2 \cdot 3} : \frac{12 + 6}{3}

x = \frac{- ( - 24 ) - 2 6}{2 \cdot 3} : \frac{12 - 6}{3}

The solutions to the quadratic equation are:

x = \frac{12 + 6}{3}, x = \frac{12 - 6}{3}

x^{2} + 1 \geq 0

\frac{5 - 2 x}{6} \leq \frac{1}{4} - \frac{3 x}{2}

3 = \frac{1}{3} (1) + b

z^{2} + 10 z + 9

2 x^{3} + x^{2} - 6 x

What are the solutions to the equation 3x^2-24x+46=0 ?
The solutions to the equation 3x^2-24x+46=0 are x=(12+sqrt(6))/3 ,x=(12-sqrt(6))/3
Find the zeros of 3x^2-24x+46=0
The zeros of 3x^2-24x+46=0 are x=(12+sqrt(6))/3 ,x=(12-sqrt(6))/3