What are the solutions to the equation x^2-16x=-68 ?

The solutions to the equation x^2-16x=-68 are x=8+2i,x=8-2i

Find the zeros of x^2-16x=-68

The zeros of x^2-16x=-68 are x=8+2i,x=8-2i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 16 x = - 68

x = 8 + 2 i, x = 8 - 2 i

Solution steps

x^{2} - 16 x = - 68

Move

68

to the left side

x^{2} - 16 x + 68 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 68}{2 \cdot 1}

Simplify

(- 16)^{2} - 4 \cdot 1 \cdot 68 : 4 i

x_{1, 2} = \frac{- ( - 16 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 16 ) + 4 i}{2 \cdot 1} : 8 + 2 i

x = \frac{- ( - 16 ) - 4 i}{2 \cdot 1} : 8 - 2 i

The solutions to the quadratic equation are:

x = 8 + 2 i, x = 8 - 2 i

3 x (x - 6) = 0

\frac{2}{( 2 + 1 ) ^{3}}

\frac{- 48}{- 6}

e^{l n (8)}

∣ 5 x - 5 ∣ = 0

What are the solutions to the equation x^2-16x=-68 ?
The solutions to the equation x^2-16x=-68 are x=8+2i,x=8-2i
Find the zeros of x^2-16x=-68
The zeros of x^2-16x=-68 are x=8+2i,x=8-2i