What are the solutions to the equation 6x^2+12x+7=0 ?

The solutions to the equation 6x^2+12x+7=0 are x=-1+i(sqrt(6))/6 ,x=-1-i(sqrt(6))/6

Find the zeros of 6x^2+12x+7=0

The zeros of 6x^2+12x+7=0 are x=-1+i(sqrt(6))/6 ,x=-1-i(sqrt(6))/6

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6 x^{2} + 12 x + 7 = 0

x = - 1 + i \frac{6}{6}, x = - 1 - i \frac{6}{6}

Solution steps

6 x^{2} + 12 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 \cdot 7}{2 \cdot 6}

Simplify

1 2^{2} - 4 \cdot 6 \cdot 7 : 26 i

x_{1, 2} = \frac{- 12 \pm 2 6 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 12 + 2 6 i}{2 \cdot 6}, x_{2} = \frac{- 12 - 2 6 i}{2 \cdot 6}

x = \frac{- 12 + 2 6 i}{2 \cdot 6} : - 1 + i \frac{6}{6}

x = \frac{- 12 - 2 6 i}{2 \cdot 6} : - 1 - i \frac{6}{6}

The solutions to the quadratic equation are:

x = - 1 + i \frac{6}{6}, x = - 1 - i \frac{6}{6}

6 (- 6 + x) = 76 - 2 x

x - 2 > 4

\frac{5}{6} - \frac{1}{8}

- 4 n - 5 (10 n + 5) < - 8 n - 1 - 6 n

\frac{x}{7} - 8 = 16

What are the solutions to the equation 6x^2+12x+7=0 ?
The solutions to the equation 6x^2+12x+7=0 are x=-1+i(sqrt(6))/6 ,x=-1-i(sqrt(6))/6
Find the zeros of 6x^2+12x+7=0
The zeros of 6x^2+12x+7=0 are x=-1+i(sqrt(6))/6 ,x=-1-i(sqrt(6))/6