What are the solutions to the equation h^2-4h+4=18 ?

The solutions to the equation h^2-4h+4=18 are h=2+3sqrt(2),h=2-3sqrt(2)

Find the zeros of h^2-4h+4=18

The zeros of h^2-4h+4=18 are h=2+3sqrt(2),h=2-3sqrt(2)

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h^{2} - 4 h + 4 = 18

h = 2 + 32, h = 2 - 32

Decimal Notation

h = 6.24264 \dots, h = - 2.24264 \dots

Solution steps

h^{2} - 4 h + 4 = 18

Move

18

to the left side

h^{2} - 4 h - 14 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 14) = 62

h_{1, 2} = \frac{- ( - 4 ) \pm 6 2}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- ( - 4 ) + 6 2}{2 \cdot 1}, h_{2} = \frac{- ( - 4 ) - 6 2}{2 \cdot 1}

h = \frac{- ( - 4 ) + 6 2}{2 \cdot 1} : 2 + 32

h = \frac{- ( - 4 ) - 6 2}{2 \cdot 1} : 2 - 32

The solutions to the quadratic equation are:

h = 2 + 32, h = 2 - 32

t^{2} - 21 t + 110 = 0

3 t^{2} + 13 t + 14

\frac{1}{2} \cdot 50

x^{2} + 11 x < - 18

(- p + 34) \cdot 7 > 49

What are the solutions to the equation h^2-4h+4=18 ?
The solutions to the equation h^2-4h+4=18 are h=2+3sqrt(2),h=2-3sqrt(2)
Find the zeros of h^2-4h+4=18
The zeros of h^2-4h+4=18 are h=2+3sqrt(2),h=2-3sqrt(2)