What are the solutions to the equation t^2-21t+110=0 ?

The solutions to the equation t^2-21t+110=0 are t=11,t=10

Find the zeros of t^2-21t+110=0

The zeros of t^2-21t+110=0 are t=11,t=10

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t^{2} - 21 t + 110 = 0

t = 11, t = 10

Solution steps

t^{2} - 21 t + 110 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 1 \cdot 110}{2 \cdot 1}

(- 21)^{2} - 4 \cdot 1 \cdot 110 = 1

t_{1, 2} = \frac{- ( - 21 ) \pm 1}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 21 ) + 1}{2 \cdot 1}, t_{2} = \frac{- ( - 21 ) - 1}{2 \cdot 1}

t = \frac{- ( - 21 ) + 1}{2 \cdot 1} : 11

t = \frac{- ( - 21 ) - 1}{2 \cdot 1} : 10

The solutions to the quadratic equation are:

t = 11, t = 10

3 t^{2} + 13 t + 14

\frac{1}{2} \cdot 50

x^{2} + 11 x < - 18

(- p + 34) \cdot 7 > 49

\frac{12}{8 n - 28}

What are the solutions to the equation t^2-21t+110=0 ?
The solutions to the equation t^2-21t+110=0 are t=11,t=10
Find the zeros of t^2-21t+110=0
The zeros of t^2-21t+110=0 are t=11,t=10