What are the solutions to the equation p^2+2p+1=0 ?

The solutions to the equation p^2+2p+1=0 are p=-1

Find the zeros of p^2+2p+1=0

The zeros of p^2+2p+1=0 are p=-1

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p^{2} + 2 p + 1 = 0

p = - 1

Solution steps

p^{2} + 2 p + 1 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

p_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

p = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

p = - 1

The solution to the quadratic equation is:

p = - 1

7 y \geq - 21

24.93 = 0.375 x^{2} + 7.235

4 (2 x - 8) = 3 (2 - 3 x)

- 2 < x \leq 2

2 (5 g - 1) = 3

What are the solutions to the equation p^2+2p+1=0 ?
The solutions to the equation p^2+2p+1=0 are p=-1
Find the zeros of p^2+2p+1=0
The zeros of p^2+2p+1=0 are p=-1