What is factor 49y^2-56y+16 ?

The solution to factor 49y^2-56y+16 is (7y-4)^2

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factor 49y^2-56y+16

factor

49 y^{2} - 56 y + 16

(7 y - 4)^{2}

Solution steps

49 y^{2} - 56 y + 16

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

49 y^{2} = (7 y)^{2}

16 = 4^{2}

- 56 y = - 2 \cdot 7 y \cdot 4

= (7 y)^{2} - 2 \cdot 7 y \cdot 4 + 4^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(7 y)^{2} - 2 \cdot 7 y \cdot 4 + 4^{2} = (7 y - 4)^{2}

= (7 y - 4)^{2}

- 8 < 6 x - 2 < 7

\frac{( 3 ^{n + 1} ) ( 9 ^{2 n} )}{27 n}

\frac{π}{\frac{2}{2}}

- \frac{6}{5} - (- \frac{1}{3})

- 4 x - 2 x + 3 x = 24