What are the solutions to the equation 0=3x^2-x-2 ?

The solutions to the equation 0=3x^2-x-2 are x=1,x=-2/3

Find the zeros of 0=3x^2-x-2

The zeros of 0=3x^2-x-2 are x=1,x=-2/3

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0 = 3 x^{2} - x - 2

x = 1, x = - \frac{2}{3}

Solution steps

0 = 3 x^{2} - x - 2

Switch sides

3 x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 2) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 3}

x = \frac{- ( - 1 ) + 5}{2 \cdot 3} : 1

x = \frac{- ( - 1 ) - 5}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{2}{3}

y - 15 = - 78

2 (11 c - \frac{33}{2} d)

\frac{3}{7} (\frac{2}{3} k - \frac{5}{6}) = \frac{5}{14}

(p^{\frac{3}{2}})^{\frac{7}{2}}

\frac{1 \cdot 1 0 ^{- 14}}{1.8 \cdot 1 0 ^{- 5}}

What are the solutions to the equation 0=3x^2-x-2 ?
The solutions to the equation 0=3x^2-x-2 are x=1,x=-2/3
Find the zeros of 0=3x^2-x-2
The zeros of 0=3x^2-x-2 are x=1,x=-2/3