What is the answer to |3a+1|=|2a-4| ?

The answer to |3a+1|=|2a-4| is a=-5\lor a= 3/5

Solve for a: |3a+1|=|2a-4|

The solution is a=-5\lor a= 3/5

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∣ 3 a + 1 ∣ = ∣ 2 a - 4 ∣

a = - 5 or a = \frac{3}{5}

Decimal Notation

a = - 5, a = 0.6

Solution steps

∣ 3 a + 1 ∣ = ∣ 2 a - 4 ∣

Find positive and negative intervals

a < - \frac{1}{3}, - \frac{1}{3} \leq a < 2, a \geq 2

Solve the inequality for each interval

a = - 5 or a = \frac{3}{5} or No Solution

a = - 5 or a = \frac{3}{5}

2 \cdot 53

6 x^{2} + 5 x - 21

q^{2} = - 1

n^{2} + 5 n - 6

5 - 3 y - (4 - 2 y) = y - 8 - (y - 1)

What is the answer to |3a+1|=|2a-4| ?
The answer to |3a+1|=|2a-4| is a=-5\lor a= 3/5
Solve for a: |3a+1|=|2a-4|
The solution is a=-5\lor a= 3/5