What is factor b^2-4b-5 ?

The solution to factor b^2-4b-5 is (b+1)(b-5)

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factor b^2-4b-5

factor

b^{2} - 4 b - 5

(b + 1) (b - 5)

Solution steps

b^{2} - 4 b - 5

Break the expression into groups

= (b^{2} + b) + (- 5 b - 5)

Factor out

b

from

b^{2} + b : b (b + 1)

Factor out

- 5

from

- 5 b - 5 : - 5 (b + 1)

= b (b + 1) - 5 (b + 1)

Factor out common term

b + 1

= (b + 1) (b - 5)

5 v^{2} - 26 v = 24

\frac{ln ( 2 )}{0.5}

∣ x + 2 ∣ \geq ∣ x - 3 ∣ - ∣ x - 2 ∣

\frac{1}{7} - \frac{1}{2}

\frac{9}{4} + \frac{9}{4}