What are the solutions to the equation -x^2+6x-5=0 ?

The solutions to the equation -x^2+6x-5=0 are x=1,x=5

Find the zeros of -x^2+6x-5=0

The zeros of -x^2+6x-5=0 are x=1,x=5

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- x^{2} + 6 x - 5 = 0

x = 1, x = 5

Solution steps

- x^{2} + 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 5 )}{2 ( - 1 )}

6^{2} - 4 (- 1) (- 5) = 4

x_{1, 2} = \frac{- 6 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 4}{2 ( - 1 )}, x_{2} = \frac{- 6 - 4}{2 ( - 1 )}

x = \frac{- 6 + 4}{2 ( - 1 )} : 1

x = \frac{- 6 - 4}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

x = 1, x = 5

5 x^{2} + 15 x + 1 = 0

60 x = 65 (4 - x)

lo g_{27} (81) = x

- 7.23 - 32.4

\frac{2}{5} \cdot \frac{3}{6} \cdot \frac{10}{7}

What are the solutions to the equation -x^2+6x-5=0 ?
The solutions to the equation -x^2+6x-5=0 are x=1,x=5
Find the zeros of -x^2+6x-5=0
The zeros of -x^2+6x-5=0 are x=1,x=5