What are the solutions to the equation r^2-6r+6=0 ?

The solutions to the equation r^2-6r+6=0 are r=3+sqrt(3),r=3-sqrt(3)

Find the zeros of r^2-6r+6=0

The zeros of r^2-6r+6=0 are r=3+sqrt(3),r=3-sqrt(3)

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r^{2} - 6 r + 6 = 0

r = 3 + 3, r = 3 - 3

Decimal Notation

r = 4.73205 \dots, r = 1.26794 \dots

Solution steps

r^{2} - 6 r + 6 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 6 = 23

r_{1, 2} = \frac{- ( - 6 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 6 ) + 2 3}{2 \cdot 1}, r_{2} = \frac{- ( - 6 ) - 2 3}{2 \cdot 1}

r = \frac{- ( - 6 ) + 2 3}{2 \cdot 1} : 3 + 3

r = \frac{- ( - 6 ) - 2 3}{2 \cdot 1} : 3 - 3

The solutions to the quadratic equation are:

r = 3 + 3, r = 3 - 3

4 (v - 2) - 3 v = 2 (v - 6)

x^{2} - 8 x + 15 < 0

- x^{2} + 5 x - 8 = 0

\frac{y ^{- 2} y ^{6}}{x ^{- 7} x ^{6}}

\frac{2 x + 2}{4} \geq 2

What are the solutions to the equation r^2-6r+6=0 ?
The solutions to the equation r^2-6r+6=0 are r=3+sqrt(3),r=3-sqrt(3)
Find the zeros of r^2-6r+6=0
The zeros of r^2-6r+6=0 are r=3+sqrt(3),r=3-sqrt(3)