What is factor 8y^4+20y^3+8y^2 ?

The solution to factor 8y^4+20y^3+8y^2 is 4y^2(2y+1)(y+2)

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factor 8y^4+20y^3+8y^2

factor

8 y^{4} + 20 y^{3} + 8 y^{2}

4 y^{2} (2 y + 1) (y + 2)

Solution steps

8 y^{4} + 20 y^{3} + 8 y^{2}

Factor out common term

4 y^{2} : 4 y^{2} (2 y^{2} + 5 y + 2)

= 4 y^{2} (2 y^{2} + 5 y + 2)

Factor

2 y^{2} + 5 y + 2 : (2 y + 1) (y + 2)

= 4 y^{2} (2 y + 1) (y + 2)

2 i^{4}

3 x^{2} + 6 x - 24 x - 48

3 m^{2} - m - 30

2 t - 3 > - 3 and 5 t - \frac{4}{5} > 8

3 (x - 3) = 5 x - 4 + 3 (7 - x)

What is factor 8y^4+20y^3+8y^2 ?
The solution to factor 8y^4+20y^3+8y^2 is 4y^2(2y+1)(y+2)