What are the solutions to the equation -4x^2=-13x+15 ?

The solutions to the equation -4x^2=-13x+15 are x= 13/8-i(sqrt(71))/8 ,x= 13/8+i(sqrt(71))/8

Find the zeros of -4x^2=-13x+15

The zeros of -4x^2=-13x+15 are x= 13/8-i(sqrt(71))/8 ,x= 13/8+i(sqrt(71))/8

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- 4 x^{2} = - 13 x + 15

x = \frac{13}{8} - i \frac{71}{8}, x = \frac{13}{8} + i \frac{71}{8}

Solution steps

- 4 x^{2} = - 13 x + 15

Move

15

to the left side

- 4 x^{2} - 15 = - 13 x

Move

13 x

to the left side

- 4 x^{2} - 15 + 13 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 13 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 ( - 4 ) ( - 15 )}{2 ( - 4 )}

Simplify

1 3^{2} - 4 (- 4) (- 15) : 71 i

x_{1, 2} = \frac{- 13 \pm 71 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 13 + 71 i}{2 ( - 4 )}, x_{2} = \frac{- 13 - 71 i}{2 ( - 4 )}

x = \frac{- 13 + 71 i}{2 ( - 4 )} : \frac{13}{8} - i \frac{71}{8}

x = \frac{- 13 - 71 i}{2 ( - 4 )} : \frac{13}{8} + i \frac{71}{8}

The solutions to the quadratic equation are:

x = \frac{13}{8} - i \frac{71}{8}, x = \frac{13}{8} + i \frac{71}{8}

6 x^{2} + 27 x + 12

(x + 4 i) (x - 4 i)

7 x + 11 x = 144

\frac{8}{2 + 5}

240

What are the solutions to the equation -4x^2=-13x+15 ?
The solutions to the equation -4x^2=-13x+15 are x= 13/8-i(sqrt(71))/8 ,x= 13/8+i(sqrt(71))/8
Find the zeros of -4x^2=-13x+15
The zeros of -4x^2=-13x+15 are x= 13/8-i(sqrt(71))/8 ,x= 13/8+i(sqrt(71))/8