What are the solutions to the equation x^2+4x=10 ?

The solutions to the equation x^2+4x=10 are x=-2+sqrt(14),x=-2-sqrt(14)

Find the zeros of x^2+4x=10

The zeros of x^2+4x=10 are x=-2+sqrt(14),x=-2-sqrt(14)

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x^{2} + 4 x = 10

x = - 2 + 14, x = - 2 - 14

Decimal Notation

x = 1.74165 \dots, x = - 5.74165 \dots

Solution steps

x^{2} + 4 x = 10

Move

10

to the left side

x^{2} + 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 10) = 214

x_{1, 2} = \frac{- 4 \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 14}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 14}{2 \cdot 1}

x = \frac{- 4 + 2 14}{2 \cdot 1} : - 2 + 14

x = \frac{- 4 - 2 14}{2 \cdot 1} : - 2 - 14

The solutions to the quadratic equation are:

x = - 2 + 14, x = - 2 - 14

(\frac{- t}{3})^{2}

6 i (5 - 2 i)

\frac{2}{\frac{4}{3}}

48 x + 56 x y

(48)^{\frac{1}{4}}

What are the solutions to the equation x^2+4x=10 ?
The solutions to the equation x^2+4x=10 are x=-2+sqrt(14),x=-2-sqrt(14)
Find the zeros of x^2+4x=10
The zeros of x^2+4x=10 are x=-2+sqrt(14),x=-2-sqrt(14)