What are the solutions to the equation 4+5b-3b^2=5 ?

The solutions to the equation 4+5b-3b^2=5 are b=(5-sqrt(13))/6 ,b=(5+sqrt(13))/6

Find the zeros of 4+5b-3b^2=5

The zeros of 4+5b-3b^2=5 are b=(5-sqrt(13))/6 ,b=(5+sqrt(13))/6

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4 + 5 b - 3 b^{2} = 5

b = \frac{5 - 13}{6}, b = \frac{5 + 13}{6}

Solution steps

4 + 5 b - 3 b^{2} = 5

Move

5

to the left side

- 3 b^{2} + 5 b - 1 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 3 ) ( - 1 )}{2 ( - 3 )}

5^{2} - 4 (- 3) (- 1) = 13

b_{1, 2} = \frac{- 5 \pm 13}{2 ( - 3 )}

Separate the solutions

b_{1} = \frac{- 5 + 13}{2 ( - 3 )}, b_{2} = \frac{- 5 - 13}{2 ( - 3 )}

b = \frac{- 5 + 13}{2 ( - 3 )} : \frac{5 - 13}{6}

b = \frac{- 5 - 13}{2 ( - 3 )} : \frac{5 + 13}{6}

The solutions to the quadratic equation are:

b = \frac{5 - 13}{6}, b = \frac{5 + 13}{6}

5 + \frac{x}{- 4} \leq 6

- 160

\frac{97}{60} + \frac{53}{30}

(\frac{32 x ^{5}}{243 y ^{20}})^{- \frac{3}{5}}

x^{2} - 2 x - 80

What are the solutions to the equation 4+5b-3b^2=5 ?
The solutions to the equation 4+5b-3b^2=5 are b=(5-sqrt(13))/6 ,b=(5+sqrt(13))/6
Find the zeros of 4+5b-3b^2=5
The zeros of 4+5b-3b^2=5 are b=(5-sqrt(13))/6 ,b=(5+sqrt(13))/6