What are the solutions to the equation 2y^2-9y+10=0 ?

The solutions to the equation 2y^2-9y+10=0 are y= 5/2 ,y=2

Find the zeros of 2y^2-9y+10=0

The zeros of 2y^2-9y+10=0 are y= 5/2 ,y=2

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2 y^{2} - 9 y + 10 = 0

y = \frac{5}{2}, y = 2

Decimal Notation

y = 2.5, y = 2

Solution steps

2 y^{2} - 9 y + 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 \cdot 10 = 1

y_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 2}, y_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 2}

y = \frac{- ( - 9 ) + 1}{2 \cdot 2} : \frac{5}{2}

y = \frac{- ( - 9 ) - 1}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

y = \frac{5}{2}, y = 2

2 x^{2} + 7 x y - 15 y^{2}

(2 b^{4})^{- 1}

(\frac{2}{3})^{- 2} \cdot (\frac{3}{2})^{- 3}

x^{2} - 4 x - 14 = 0

x = \frac{4 ( - 7 )}{( - 7 ) - 3}

What are the solutions to the equation 2y^2-9y+10=0 ?
The solutions to the equation 2y^2-9y+10=0 are y= 5/2 ,y=2
Find the zeros of 2y^2-9y+10=0
The zeros of 2y^2-9y+10=0 are y= 5/2 ,y=2