What is sqrt(x-1)>= 0 ?

The solution to sqrt(x-1)>= 0 is x>= 1

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sqrt(x-1)>= 0

x - 1 \geq 0

x \geq 1

Interval Notation

[1, \infty)

Solution steps

x - 1 \geq 0

If n is even,

for all

u

True for all x

Find singularity points

Find non-negative values for radicals:

x \geq 1

Combine the intervals

True for all x and x \geq 1

Merge Overlapping Intervals

x \geq 1

27 x^{2} - 36 x y + 12 y^{2}

x^{2} - 20 x + 99 > 0

2 + 2 x - 5 = (x + 3)

\frac{2 a ^{3} - 2 a}{2 a}

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