What is 2p+3-1>=-(p-3)-2(2p+4) ?

The solution to 2p+3-1>=-(p-3)-2(2p+4) is p>=-1

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2p+3-1>=-(p-3)-2(2p+4)

2 p + 3 - 1 \geq - (p - 3) - 2 (2 p + 4)

p \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

2 p + 3 - 1 \geq - (p - 3) - 2 (2 p + 4)

Add/Subtract the numbers:

3 - 1 = 2

2 p + 2 \geq - (p - 3) - 2 (2 p + 4)

Expand

- (p - 3) - 2 (2 p + 4) : - 5 p - 5

2 p + 2 \geq - 5 p - 5

Move

2

to the right side

2 p \geq - 5 p - 7

Move

5 p

to the left side

7 p \geq - 7

Divide both sides by

7

p \geq - 1

x^{2} = x

5 x^{2} + 2 x + 10 = 0

- \frac{1}{2} (2)^{- 1}

- 28 = \frac{4}{5} d

- 19 = b - 6

What is 2p+3-1>=-(p-3)-2(2p+4) ?
The solution to 2p+3-1>=-(p-3)-2(2p+4) is p>=-1