What is the answer to (3x-7(x+1))/6 =(2x-1)/3-2 ?

The answer to (3x-7(x+1))/6 =(2x-1)/3-2 is x= 7/8

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(3x-7(x+1))/6 =(2x-1)/3-2

\frac{3 x - 7 ( x + 1 )}{6} = \frac{2 x - 1}{3} - 2

x = \frac{7}{8}

Decimal Notation

x = 0.875

Solution steps

\frac{3 x - 7 ( x + 1 )}{6} = \frac{2 x - 1}{3} - 2

Multiply by LCM

3 x - 7 (x + 1) = 2 (2 x - 1) - 12

Expand

- 7 (x + 1) : - 7 x - 7

3 x - 7 x - 7 = 2 (2 x - 1) - 12

Add similar elements:

3 x - 7 x = - 4 x

- 4 x - 7 = 2 (2 x - 1) - 12

Expand

2 (2 x - 1) - 12 : 4 x - 14

- 4 x - 7 = 4 x - 14

Move

7

to the right side

- 4 x = 4 x - 7

Move

4 x

to the left side

- 8 x = - 7

Divide both sides by

- 8

x = \frac{7}{8}

x^{2} - \frac{1}{25}

17 = 5 - 6 x - x^{2}

- 4 - 3

x \leq - 5 and x \leq - 3

lo g_{2} (x^{2} - 6 x) \leq 3 + lo g_{2} (1 - x)

What is the answer to (3x-7(x+1))/6 =(2x-1)/3-2 ?
The answer to (3x-7(x+1))/6 =(2x-1)/3-2 is x= 7/8
Solve for x: (3x-7(x+1))/6 =(2x-1)/3-2
The solution is x= 7/8