What are the solutions to the equation 2x^2+5x-9=0 ?

The solutions to the equation 2x^2+5x-9=0 are x=(-5+sqrt(97))/4 ,x=(-5-sqrt(97))/4

Find the zeros of 2x^2+5x-9=0

The zeros of 2x^2+5x-9=0 are x=(-5+sqrt(97))/4 ,x=(-5-sqrt(97))/4

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2 x^{2} + 5 x - 9 = 0

x = \frac{- 5 + 97}{4}, x = \frac{- 5 - 97}{4}

Decimal Notation

x = 1.21221 \dots, x = - 3.71221 \dots

Solution steps

2 x^{2} + 5 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 9) = 97

x_{1, 2} = \frac{- 5 \pm 97}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 97}{2 \cdot 2}, x_{2} = \frac{- 5 - 97}{2 \cdot 2}

x = \frac{- 5 + 97}{2 \cdot 2} : \frac{- 5 + 97}{4}

x = \frac{- 5 - 97}{2 \cdot 2} : \frac{- 5 - 97}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 97}{4}, x = \frac{- 5 - 97}{4}

(2^{2})^{\frac{3}{2}}

- \frac{π}{2} - \frac{π}{4}

5 x^{2} = x

n^{2} - 12 n + 11

3 x^{2} + 13 x - 28 = 2 x^{2} + 2

What are the solutions to the equation 2x^2+5x-9=0 ?
The solutions to the equation 2x^2+5x-9=0 are x=(-5+sqrt(97))/4 ,x=(-5-sqrt(97))/4
Find the zeros of 2x^2+5x-9=0
The zeros of 2x^2+5x-9=0 are x=(-5+sqrt(97))/4 ,x=(-5-sqrt(97))/4