What is |x^3|-x+3>= 3 ?

The solution to |x^3|-x+3>= 3 is x = 1

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|x^3|-x+3>= 3

x^{3} - x + 3 \geq 3

x \leq 0 or x \geq 1

Interval Notation

(- \infty, 0] \cup [1, \infty)

Solution steps

x^{3} - x + 3 \geq 3

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

x < 0 or (x = 0 or x \geq 1)

Merge Overlapping Intervals

x \leq 0 or x \geq 1

x + 6 > 9

0.8 x + 20 < 1.2 x - 40

e^{l n (15)}

\frac{1}{8} = 8 x

\frac{7 x - 16}{2} = 2 x - 3