What are the solutions to the equation -2(y+7)^2=-128 ?

The solutions to the equation -2(y+7)^2=-128 are y=1,y=-15

Find the zeros of -2(y+7)^2=-128

The zeros of -2(y+7)^2=-128 are y=1,y=-15

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- 2 (y + 7)^{2} = - 128

y = 1, y = - 15

Solution steps

- 2 (y + 7)^{2} = - 128

Divide both sides by

- 2

(y + 7)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 7 = 64 : y = 1

Solve

y + 7 = - 64 : y = - 15

The solutions to the quadratic equation are:

y = 1, y = - 15

\frac{2}{3} + \frac{7}{3}

5 ∣ x - 4 ∣ - 7 = 2

3 x + 9 = - 24

15 c \geq 200

3 y^{2} - y - 4 = 0

What are the solutions to the equation -2(y+7)^2=-128 ?
The solutions to the equation -2(y+7)^2=-128 are y=1,y=-15
Find the zeros of -2(y+7)^2=-128
The zeros of -2(y+7)^2=-128 are y=1,y=-15