What are the solutions to the equation z^2+10z+5=-11 ?

The solutions to the equation z^2+10z+5=-11 are z=-2,z=-8

Find the zeros of z^2+10z+5=-11

The zeros of z^2+10z+5=-11 are z=-2,z=-8

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z^{2} + 10 z + 5 = - 11

z = - 2, z = - 8

Solution steps

z^{2} + 10 z + 5 = - 11

Move

11

to the left side

z^{2} + 10 z + 16 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 16 = 6

z_{1, 2} = \frac{- 10 \pm 6}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 10 + 6}{2 \cdot 1}, z_{2} = \frac{- 10 - 6}{2 \cdot 1}

z = \frac{- 10 + 6}{2 \cdot 1} : - 2

z = \frac{- 10 - 6}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

z = - 2, z = - 8

10 x y + 20 x + 14 y + 28

lo g_{8} (512)

6 x^{2} + 30 x = 0

- 4 x + 8 = - 3 x + 2

\frac{21 !}{( 21 - 8 ) ! 8 !}

What are the solutions to the equation z^2+10z+5=-11 ?
The solutions to the equation z^2+10z+5=-11 are z=-2,z=-8
Find the zeros of z^2+10z+5=-11
The zeros of z^2+10z+5=-11 are z=-2,z=-8