What are the solutions to the equation 0=x^2-9x+18 ?

The solutions to the equation 0=x^2-9x+18 are x=6,x=3

Find the zeros of 0=x^2-9x+18

The zeros of 0=x^2-9x+18 are x=6,x=3

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0 = x^{2} - 9 x + 18

x = 6, x = 3

Solution steps

0 = x^{2} - 9 x + 18

Switch sides

x^{2} - 9 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

x_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

x = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

x = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 6, x = 3

9 m x - 9 n x + 6 m y - 6 n y + 12 m z - 12 n z

(x^{2} + 4)^{\frac{3}{2}}

(x - 1)^{\frac{7}{2}} - (x - 1)^{\frac{3}{2}}

15 x + 18 \leq x^{2} (2 x + 1)

4 x^{2} + 4 x = 15

What are the solutions to the equation 0=x^2-9x+18 ?
The solutions to the equation 0=x^2-9x+18 are x=6,x=3
Find the zeros of 0=x^2-9x+18
The zeros of 0=x^2-9x+18 are x=6,x=3