What are the solutions to the equation 7x^2+3x=8 ?

The solutions to the equation 7x^2+3x=8 are x=(-3+sqrt(233))/(14),x=(-3-sqrt(233))/(14)

Find the zeros of 7x^2+3x=8

The zeros of 7x^2+3x=8 are x=(-3+sqrt(233))/(14),x=(-3-sqrt(233))/(14)

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7 x^{2} + 3 x = 8

x = \frac{- 3 + 233}{14}, x = \frac{- 3 - 233}{14}

Decimal Notation

x = 0.87602 \dots, x = - 1.30459 \dots

Solution steps

7 x^{2} + 3 x = 8

Move

8

to the left side

7 x^{2} + 3 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 7 ( - 8 )}{2 \cdot 7}

3^{2} - 4 \cdot 7 (- 8) = 233

x_{1, 2} = \frac{- 3 \pm 233}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 3 + 233}{2 \cdot 7}, x_{2} = \frac{- 3 - 233}{2 \cdot 7}

x = \frac{- 3 + 233}{2 \cdot 7} : \frac{- 3 + 233}{14}

x = \frac{- 3 - 233}{2 \cdot 7} : \frac{- 3 - 233}{14}

The solutions to the quadratic equation are:

x = \frac{- 3 + 233}{14}, x = \frac{- 3 - 233}{14}

\frac{( x - 5 ) ( 2 x + 3 )}{( x - 1 ) ^{2}} \leq 0

64 u^{3} - v^{3}

2 m^{2} - 11 m + 15

- \frac{1}{4} (- 4)

x^{3} + 6 x^{2} - 16 x

What are the solutions to the equation 7x^2+3x=8 ?
The solutions to the equation 7x^2+3x=8 are x=(-3+sqrt(233))/(14),x=(-3-sqrt(233))/(14)
Find the zeros of 7x^2+3x=8
The zeros of 7x^2+3x=8 are x=(-3+sqrt(233))/(14),x=(-3-sqrt(233))/(14)