What are the solutions to the equation 3x^2+17x+14=0 ?

The solutions to the equation 3x^2+17x+14=0 are x=-1,x=-14/3

Find the zeros of 3x^2+17x+14=0

The zeros of 3x^2+17x+14=0 are x=-1,x=-14/3

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3 x^{2} + 17 x + 14 = 0

x = - 1, x = - \frac{14}{3}

Decimal Notation

x = - 1, x = - 4.66666 \dots

Solution steps

3 x^{2} + 17 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 \cdot 14}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 \cdot 14 = 11

x_{1, 2} = \frac{- 17 \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 17 + 11}{2 \cdot 3}, x_{2} = \frac{- 17 - 11}{2 \cdot 3}

x = \frac{- 17 + 11}{2 \cdot 3} : - 1

x = \frac{- 17 - 11}{2 \cdot 3} : - \frac{14}{3}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{14}{3}

e^{\frac{9}{2}}

360 - 10 t^{2}

27 t^{3} - 125 q^{3}

\frac{h}{- 4} = 21

(\frac{5}{3})^{5}

What are the solutions to the equation 3x^2+17x+14=0 ?
The solutions to the equation 3x^2+17x+14=0 are x=-1,x=-14/3
Find the zeros of 3x^2+17x+14=0
The zeros of 3x^2+17x+14=0 are x=-1,x=-14/3