What are the solutions to the equation 4x^2+12x-7=0 ?

The solutions to the equation 4x^2+12x-7=0 are x= 1/2 ,x=-7/2

Find the zeros of 4x^2+12x-7=0

The zeros of 4x^2+12x-7=0 are x= 1/2 ,x=-7/2

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4 x^{2} + 12 x - 7 = 0

x = \frac{1}{2}, x = - \frac{7}{2}

Decimal Notation

x = 0.5, x = - 3.5

Solution steps

4 x^{2} + 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 7) = 16

x_{1, 2} = \frac{- 12 \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 16}{2 \cdot 4}, x_{2} = \frac{- 12 - 16}{2 \cdot 4}

x = \frac{- 12 + 16}{2 \cdot 4} : \frac{1}{2}

x = \frac{- 12 - 16}{2 \cdot 4} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{7}{2}

9 x - 27

y^{2} + 18 y + 81

8 x^{2} + 14 x + 40

2 x^{2} - 3 x - 9

25 x^{2} + 10 x y + y^{2}

What are the solutions to the equation 4x^2+12x-7=0 ?
The solutions to the equation 4x^2+12x-7=0 are x= 1/2 ,x=-7/2
Find the zeros of 4x^2+12x-7=0
The zeros of 4x^2+12x-7=0 are x= 1/2 ,x=-7/2