What are the solutions to the equation 5^2=1^2+x^2 ?

The solutions to the equation 5^2=1^2+x^2 are x=2sqrt(6),x=-2sqrt(6)

Find the zeros of 5^2=1^2+x^2

The zeros of 5^2=1^2+x^2 are x=2sqrt(6),x=-2sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5^{2} = 1^{2} + x^{2}

x = 26, x = - 26

Decimal Notation

x = 4.89897 \dots, x = - 4.89897 \dots

Solution steps

5^{2} = 1^{2} + x^{2}

Switch sides

1^{2} + x^{2} = 5^{2}

Move

1^{2}

to the right side

x^{2} = 24

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 24, x = - 24

24 = 26

- 24 = - 26

x = 26, x = - 26

g^{3} - 343

∣ x - 1 ∣ = 3

x^{- 2} \cdot x^{\frac{11}{9}}

2 w x + 10 w + 7 x + 35

2 x^{2} - 12 x + 4

What are the solutions to the equation 5^2=1^2+x^2 ?
The solutions to the equation 5^2=1^2+x^2 are x=2sqrt(6),x=-2sqrt(6)
Find the zeros of 5^2=1^2+x^2
The zeros of 5^2=1^2+x^2 are x=2sqrt(6),x=-2sqrt(6)