What is 2/3 <= (4x+1)/5 <4 ?

The solution to 2/3 <= (4x+1)/5 <4 is 7/12 <= x< 19/4

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2/3 <= (4x+1)/5 <4

\frac{2}{3} \leq \frac{4 x + 1}{5} < 4

\frac{7}{12} \leq x < \frac{19}{4}

Interval Notation

[\frac{7}{12}, \frac{19}{4})

Decimal Notation

0.58333 \dots \leq x < 4.75

Solution steps

\frac{2}{3} \leq \frac{4 x + 1}{5} < 4

a \leq u < b

then

a \leq u and u < b

\frac{2}{3} \leq \frac{4 x + 1}{5} and \frac{4 x + 1}{5} < 4

\frac{2}{3} \leq \frac{4 x + 1}{5} : x \geq \frac{7}{12}

\frac{4 x + 1}{5} < 4 : x < \frac{19}{4}

Combine the intervals

x \geq \frac{7}{12} and x < \frac{19}{4}

Merge Overlapping Intervals

\frac{7}{12} \leq x < \frac{19}{4}

2 (5 x + 4)^{2} - 40 = - 20

36 m^{2} - 24 m + 16 n^{2}

2 x^{2} - 10 = 0

p (9 p - 16) < 0

\frac{5}{3} \cdot 9

What is 2/3 <= (4x+1)/5 <4 ?
The solution to 2/3 <= (4x+1)/5 <4 is 7/12 <= x< 19/4