What are the solutions to the equation x^2+15x+36=0 ?

The solutions to the equation x^2+15x+36=0 are x=-3,x=-12

Find the zeros of x^2+15x+36=0

The zeros of x^2+15x+36=0 are x=-3,x=-12

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x^{2} + 15 x + 36 = 0

x = - 3, x = - 12

Solution steps

x^{2} + 15 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 36 = 9

x_{1, 2} = \frac{- 15 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 9}{2 \cdot 1}, x_{2} = \frac{- 15 - 9}{2 \cdot 1}

x = \frac{- 15 + 9}{2 \cdot 1} : - 3

x = \frac{- 15 - 9}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = - 3, x = - 12

\frac{360}{31} \cdot \frac{π}{180}

\frac{\frac{1}{3}}{\frac{3}{2}}

\frac{2 + 3 i}{1 - 5 i}

(x - 3 i) - (15 + x i) = 7 - 12 i

- 18 b = 32

What are the solutions to the equation x^2+15x+36=0 ?
The solutions to the equation x^2+15x+36=0 are x=-3,x=-12
Find the zeros of x^2+15x+36=0
The zeros of x^2+15x+36=0 are x=-3,x=-12