What are the solutions to the equation 3x^2-36=12x ?

The solutions to the equation 3x^2-36=12x are x=6,x=-2

Find the zeros of 3x^2-36=12x

The zeros of 3x^2-36=12x are x=6,x=-2

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3 x^{2} - 36 = 12 x

x = 6, x = - 2

Solution steps

3 x^{2} - 36 = 12 x

Move

12 x

to the left side

3 x^{2} - 36 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 12 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 36 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 36) = 24

x_{1, 2} = \frac{- ( - 12 ) \pm 24}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 24}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 24}{2 \cdot 3}

x = \frac{- ( - 12 ) + 24}{2 \cdot 3} : 6

x = \frac{- ( - 12 ) - 24}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

0.16 m + 25 < 60

\frac{1}{4} + \frac{11}{20}

\frac{2}{3} + \frac{1}{7}

\frac{27 x ^{5} y ^{3}}{x y ^{7}}

- 1 - (- \frac{1}{2})

What are the solutions to the equation 3x^2-36=12x ?
The solutions to the equation 3x^2-36=12x are x=6,x=-2
Find the zeros of 3x^2-36=12x
The zeros of 3x^2-36=12x are x=6,x=-2