What are the solutions to the equation -x^2+3x+5=0 ?

The solutions to the equation -x^2+3x+5=0 are x=-(-3+sqrt(29))/2 ,x=(3+sqrt(29))/2

Find the zeros of -x^2+3x+5=0

The zeros of -x^2+3x+5=0 are x=-(-3+sqrt(29))/2 ,x=(3+sqrt(29))/2

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- x^{2} + 3 x + 5 = 0

x = - \frac{- 3 + 29}{2}, x = \frac{3 + 29}{2}

Decimal Notation

x = - 1.19258 \dots, x = 4.19258 \dots

Solution steps

- x^{2} + 3 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 5}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 5 = 29

x_{1, 2} = \frac{- 3 \pm 29}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 29}{2 ( - 1 )}, x_{2} = \frac{- 3 - 29}{2 ( - 1 )}

x = \frac{- 3 + 29}{2 ( - 1 )} : - \frac{- 3 + 29}{2}

x = \frac{- 3 - 29}{2 ( - 1 )} : \frac{3 + 29}{2}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 29}{2}, x = \frac{3 + 29}{2}

∣ 4 - 5 x ∣ + 5 \geq 8

9 x^{2} + 30 + 25

t + 4 = 1

\frac{e ^{9 i} - e ^{- 9 i}}{2 i}

\frac{6 ( 2 ) ^{2} - 1}{2 ^{2}}

What are the solutions to the equation -x^2+3x+5=0 ?
The solutions to the equation -x^2+3x+5=0 are x=-(-3+sqrt(29))/2 ,x=(3+sqrt(29))/2
Find the zeros of -x^2+3x+5=0
The zeros of -x^2+3x+5=0 are x=-(-3+sqrt(29))/2 ,x=(3+sqrt(29))/2