What are the solutions to the equation 3b^2+8b+4=0 ?

The solutions to the equation 3b^2+8b+4=0 are b=-2/3 ,b=-2

Find the zeros of 3b^2+8b+4=0

The zeros of 3b^2+8b+4=0 are b=-2/3 ,b=-2

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3 b^{2} + 8 b + 4 = 0

b = - \frac{2}{3}, b = - 2

Decimal Notation

b = - 0.66666 \dots, b = - 2

Solution steps

3 b^{2} + 8 b + 4 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

8^{2} - 4 \cdot 3 \cdot 4 = 4

b_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- 8 + 4}{2 \cdot 3}, b_{2} = \frac{- 8 - 4}{2 \cdot 3}

b = \frac{- 8 + 4}{2 \cdot 3} : - \frac{2}{3}

b = \frac{- 8 - 4}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

b = - \frac{2}{3}, b = - 2

3 x^{2} + 8 x - 35

1.44

100 y^{2} = 900

- \frac{1}{3} \cdot 4

(x^{\frac{7}{6}})^{2}

What are the solutions to the equation 3b^2+8b+4=0 ?
The solutions to the equation 3b^2+8b+4=0 are b=-2/3 ,b=-2
Find the zeros of 3b^2+8b+4=0
The zeros of 3b^2+8b+4=0 are b=-2/3 ,b=-2