What are the solutions to the equation x^2+10x=-52 ?

The solutions to the equation x^2+10x=-52 are x=-5+3sqrt(3)i,x=-5-3sqrt(3)i

Find the zeros of x^2+10x=-52

The zeros of x^2+10x=-52 are x=-5+3sqrt(3)i,x=-5-3sqrt(3)i

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x^{2} + 10 x = - 52

x = - 5 + 33 i, x = - 5 - 33 i

Solution steps

x^{2} + 10 x = - 52

Move

52

to the left side

x^{2} + 10 x + 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 52}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 52 : 63 i

x_{1, 2} = \frac{- 10 \pm 6 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 6 3 i}{2 \cdot 1}, x_{2} = \frac{- 10 - 6 3 i}{2 \cdot 1}

x = \frac{- 10 + 6 3 i}{2 \cdot 1} : - 5 + 33 i

x = \frac{- 10 - 6 3 i}{2 \cdot 1} : - 5 - 33 i

The solutions to the quadratic equation are:

x = - 5 + 33 i, x = - 5 - 33 i

- 152 - 15 x = - 8 x + 79

7 x^{2} - 18 = - 39 x

\frac{7 ^{- 2}}{7 ^{- 6}}

(- \frac{1}{5})^{3}

x^{7} + y^{7}

What are the solutions to the equation x^2+10x=-52 ?
The solutions to the equation x^2+10x=-52 are x=-5+3sqrt(3)i,x=-5-3sqrt(3)i
Find the zeros of x^2+10x=-52
The zeros of x^2+10x=-52 are x=-5+3sqrt(3)i,x=-5-3sqrt(3)i