What are the solutions to the equation 2x^2-6x-9=0 ?

The solutions to the equation 2x^2-6x-9=0 are x=(3(1+sqrt(3)))/2 ,x=(3(1-sqrt(3)))/2

Find the zeros of 2x^2-6x-9=0

The zeros of 2x^2-6x-9=0 are x=(3(1+sqrt(3)))/2 ,x=(3(1-sqrt(3)))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 6 x - 9 = 0

x = \frac{3 ( 1 + 3 )}{2}, x = \frac{3 ( 1 - 3 )}{2}

Decimal Notation

x = 4.09807 \dots, x = - 1.09807 \dots

Solution steps

2 x^{2} - 6 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 9) = 63

x_{1, 2} = \frac{- ( - 6 ) \pm 6 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 3}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 6 3}{2 \cdot 2}

x = \frac{- ( - 6 ) + 6 3}{2 \cdot 2} : \frac{3 ( 1 + 3 )}{2}

x = \frac{- ( - 6 ) - 6 3}{2 \cdot 2} : \frac{3 ( 1 - 3 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 1 + 3 )}{2}, x = \frac{3 ( 1 - 3 )}{2}

\frac{- 7}{8} \leq m - \frac{13}{8}

5 x + 100 = 3 x + 112

23 - 3

- 30 y = 9 y^{2} + 25

What are the solutions to the equation 2x^2-6x-9=0 ?
The solutions to the equation 2x^2-6x-9=0 are x=(3(1+sqrt(3)))/2 ,x=(3(1-sqrt(3)))/2
Find the zeros of 2x^2-6x-9=0
The zeros of 2x^2-6x-9=0 are x=(3(1+sqrt(3)))/2 ,x=(3(1-sqrt(3)))/2