What are the solutions to the equation (x+3)^2-11=-12 ?

The solutions to the equation (x+3)^2-11=-12 are x=i-3,x=-i-3

Find the zeros of (x+3)^2-11=-12

The zeros of (x+3)^2-11=-12 are x=i-3,x=-i-3

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(x + 3)^{2} - 11 = - 12

x = i - 3, x = - i - 3

Solution steps

(x + 3)^{2} - 11 = - 12

Move

11

to the right side

(x + 3)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = - 1 : x = i - 3

Solve

x + 3 = - - 1 : x = - i - 3

The solutions to the quadratic equation are:

x = i - 3, x = - i - 3

\frac{2 y x ^{3}}{x ^{2} y ^{3}}

48 \cdot 4

\frac{a ^{2} - 9}{a ^{2} - 3 a}

y - 5 > 8

2 z^{5} - 12 z^{3} + 10 z

What are the solutions to the equation (x+3)^2-11=-12 ?
The solutions to the equation (x+3)^2-11=-12 are x=i-3,x=-i-3
Find the zeros of (x+3)^2-11=-12
The zeros of (x+3)^2-11=-12 are x=i-3,x=-i-3