What are the solutions to the equation (x-2)(x+6)=0 ?

The solutions to the equation (x-2)(x+6)=0 are x=2,x=-6

Find the zeros of (x-2)(x+6)=0

The zeros of (x-2)(x+6)=0 are x=2,x=-6

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(x - 2) (x + 6) = 0

x = 2, x = - 6

Solution steps

(x - 2) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 6 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 6 = 0 : x = - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

\frac{c}{3} = 3

\frac{2 \cdot 3 ^{2} \cdot 3 !}{( 2 \cdot 3 ) ! ( 3 + 1 ) ^{2}}

0 < x < 2

(4 + 3 i) (4 - 3 i)

\frac{2}{5} + \frac{4}{3} \frac{3}{5} - (\frac{1}{4})^{2}

What are the solutions to the equation (x-2)(x+6)=0 ?
The solutions to the equation (x-2)(x+6)=0 are x=2,x=-6
Find the zeros of (x-2)(x+6)=0
The zeros of (x-2)(x+6)=0 are x=2,x=-6