What are the solutions to the equation 8m^2+20m+13=0 ?

The solutions to the equation 8m^2+20m+13=0 are m=-5/4+i 1/4 ,m=-5/4-i 1/4

Find the zeros of 8m^2+20m+13=0

The zeros of 8m^2+20m+13=0 are m=-5/4+i 1/4 ,m=-5/4-i 1/4

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8 m^{2} + 20 m + 13 = 0

m = - \frac{5}{4} + i \frac{1}{4}, m = - \frac{5}{4} - i \frac{1}{4}

Solution steps

8 m^{2} + 20 m + 13 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 8 \cdot 13}{2 \cdot 8}

Simplify

2 0^{2} - 4 \cdot 8 \cdot 13 : 4 i

m_{1, 2} = \frac{- 20 \pm 4 i}{2 \cdot 8}

Separate the solutions

m_{1} = \frac{- 20 + 4 i}{2 \cdot 8}, m_{2} = \frac{- 20 - 4 i}{2 \cdot 8}

m = \frac{- 20 + 4 i}{2 \cdot 8} : - \frac{5}{4} + i \frac{1}{4}

m = \frac{- 20 - 4 i}{2 \cdot 8} : - \frac{5}{4} - i \frac{1}{4}

The solutions to the quadratic equation are:

m = - \frac{5}{4} + i \frac{1}{4}, m = - \frac{5}{4} - i \frac{1}{4}

70 - t > 74

- 5 t^{2} + 30 t

x^{2} + 2 x + 3 > 0

6.2 = 2.2 + x

- 229 > 5 k - 4 + 4 k

What are the solutions to the equation 8m^2+20m+13=0 ?
The solutions to the equation 8m^2+20m+13=0 are m=-5/4+i 1/4 ,m=-5/4-i 1/4
Find the zeros of 8m^2+20m+13=0
The zeros of 8m^2+20m+13=0 are m=-5/4+i 1/4 ,m=-5/4-i 1/4