What is the answer to f=\sqrt[5]{32f^4} ?

The answer to f=\sqrt[5]{32f^4} is f=0,f=32

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f=\sqrt[5]{32f^4}

f = 0, f = 32

Solution steps

Take both sides of the equation to the power of

5 : f^{5} = 32 f^{4}

f^{5} = 32 f^{4}

Solve

f^{5} = 32 f^{4} : f = 0, f = 32

f = 0, f = 32

Verify Solutions:

f = 0

True

, f = 32

True

The solutions are

f = 0, f = 32

5 x + 7 \leq - 8

\frac{x}{7} - \frac{2 x}{3} = \frac{3}{7}

\frac{x}{6} + 2 = 24

618 + 350

- 6 (2 x + 11) < - 18 x - 30

What is the answer to f=\sqrt[5]{32f^4} ?
The answer to f=\sqrt[5]{32f^4} is f=0,f=32
Solve for f: f=\sqrt[5]{32f^4}
The solution is f=0,f=32