What are the solutions to the equation 2r^2+3r+6=6 ?

The solutions to the equation 2r^2+3r+6=6 are r=0,r=-3/2

Find the zeros of 2r^2+3r+6=6

The zeros of 2r^2+3r+6=6 are r=0,r=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 r^{2} + 3 r + 6 = 6

r = 0, r = - \frac{3}{2}

Decimal Notation

r = 0, r = - 1.5

Solution steps

2 r^{2} + 3 r + 6 = 6

Move

6

to the left side

2 r^{2} + 3 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

3^{2} - 4 \cdot 2 \cdot 0 = 3

r_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- 3 + 3}{2 \cdot 2}, r_{2} = \frac{- 3 - 3}{2 \cdot 2}

r = \frac{- 3 + 3}{2 \cdot 2} : 0

r = \frac{- 3 - 3}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

r = 0, r = - \frac{3}{2}

lo g_{6} (6^{5})

3 s + 2 > 8

\frac{( \frac{2 p ^{2} + 2 p + 2 q - 10}{- p + 3} )}{2}

2 x^{2} - 3 x - 1 = 0

\frac{6 !}{6 !}

What are the solutions to the equation 2r^2+3r+6=6 ?
The solutions to the equation 2r^2+3r+6=6 are r=0,r=-3/2
Find the zeros of 2r^2+3r+6=6
The zeros of 2r^2+3r+6=6 are r=0,r=-3/2